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THE VALUE OF SPIN ONLY MAGNETIC MOMENT FOR ONE OF THE FOLLOWING CONFIGURATION IS 2.85BM.THE CORRECT ONE IN OCTAHEDRAL FIELD IS ______
(SF-STRONG FIELD, WF-WEAK FIELD)
A)d4(SF)
B)d4(WF)
C)d3(WF AND SF)
D)d5(SF)
A)d4(SF) is the correct answer.
Becoz from magnetic moment 2.85BM no. of unpaired electrons are 2.
and in octahederal configuration =
Thus 2 unpaired electrons.
PLZ APPROVE!
Bit will be root(2*4)
ans is B
pls explain the difference between SF and WF....and how to write the config. of octahedral field..?
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