If α and β are the roots of x2 + px + q = 0 and α4 and β4 are the roots of
x2 - rx + s = 0, then the equation x2 - 4qx + 2q2 - r = 0 has always
( a ) two real roots ( b ) two positive roots
( c ) two negative roots ( d ) one positive and one negative root

Dear Ayushi,

Sum of roots = -b/a

Product of roots = c/a

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