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Ankit Shukla Grade:
        

























 

A particle is projected ...at that time its kinetic energy was KE1......and at the top point where vertical velocity is 0 its kinetic energy was KE2 .......


The ratio of KE2 : KE1 is 3:4 ........ find the difference in their velocities ......




 



































Dear ankit


let velocity at the begineeing ii u and angle of projection is θ.


KE1 =1/2 mu2


KE2 =1/2 m(ucosθ)2


given


KE2 : KE1 is 3:4


so cos2θ  =3/4


θ =30


difference in their velocity =u-ucosθ


                                     =u-u√3/2


                                     =u(1-√3/2)


 


sir but answer of this is u/2 ....



7 years ago

Answers : (2)

chaitanya pansare
23 Points
										

then might be the ques. is asking the difference in vertical velocities which comes out to be usinθ-0 i.e. u/2-0=u/2

7 years ago
Badiuddin askIITians.ismu Expert
147 Points
										

Dear Ankit Shukla


last answer was on the basis of difference in velocity magnitude.


I think you want difference in velocity vector


Initial velocity =ucosΘ i + usinΘ j


final velocity =ucosΘ i


 


difference in velocity =ucosΘ i + usinΘ j -ucosΘ i


                             =usinΘ j


                            =u sin30 j


                            =u/2 j


magnitude            =|u/2 j|


                           =u/2


 





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Badiuddin

7 years ago
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