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`        The benches of a gallery of a cricket stadium are 1m high and 1m wide.A batsman strikes the ball at a level 1m above the ground and hits a mammoth sixer.The ball starts at 35 m/s at an angle of 53 degrees with the horizontal.The benches are perpendicular to the plane of motion and the first bench is 110m from the batsman.On which bench will the ball hit?          `
8 years ago

Ramesh V
70 Points
```										Range of projectile = u2.sin 2x /g
= 117.75 mts
so on the ground ,it covers 110 mts and the left distance of 7.75 mts is on gallary
each bench hz. length is 1 mts
so it lands on 8th bench
--
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```
8 years ago
rrrrrr ssss
18 Points
```										The answer to this is 6th bench.
y=(n-1)1 (because there is a 1m uplevel).
x= 110 + (n-1)
x= 110+ y
Put it in the equation of trajectory =
y = xtanA - gx^2sec^2A/2u^2
where x=110+y
sec62a = 25/9 and u = 35m/s
you will get y =5
put it in y=n-1
we will get n=6
```
4 years ago
shreyash kawalkar
18 Points
```										range= (2* u  sinA * u sinB)/g
u sinA= 35 * 4/5= 28
u sinB= 35* 3/5= 21
g=10 m/s2
range= 2*28*21/10
=42*28/10
=112.6
1st bench 110 to 111
2nd bench 111 to 112
3rd bench 112 to 113
hence, 3rd bench.
```
4 years ago
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