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I assumed you (a JEE prep. student), might be knowing that the product of Plank's constant and velocity of light can be expressed as : hc = 1242 eV-nm and 1 eV = 1.602x10-19 J
and E = h.c / wavelength
Please check the units..
I hope this makes you clear...
Radiant energy = 1242 eV-nm / 253.7 nm = 4.895 eV = 7.843x10-19 J. How this Radiant Energy = 1242 eV-nm/253.7 nm
While solving numbers of problems, it didn't click in my mind. We were not told about it in coaching class nor I saw in book. Thanks..this formula is of great use!
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