Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        find the radius R of the largest sphere that can be fitted into a cylinder of radius 'r' and height 'h' in terms of 'r' and 'h'.`
6 years ago

SAGAR SINGH - IIT DELHI
879 Points
```										Dear student,
R=radius  of  sphere     x=  the  hight of  the cylinder  r=radius  of  cylinder  r^2+x^2=(2R)^2      r^2=-x^2+4R^2  v(x)=pi*r^2*h=pi(-x^2+4R^2)*x=pi*(-x^3…   v'=pi(-3x^2+4R^2)=0    3x^2=4R^2  x^2=4R^2/3     r^2=-x^2+4R^2=-4R^2/3+4R^2=4R^2*2/3=  8R^2/3    r=sqrt(8R^2/3 )=Rsqrt(8/3)

All the best.
Win exciting gifts by                                                                                                                                                                                                                                answering             the                               questions              on                                            Discussion                                          Forum.         So                             help                                                 discuss                                any                                                   query             on                                               askiitians                        forum         and                                      become         an                             Elite                                                  Expert                           League                                                              askiitian.

Sagar Singh
B.Tech, IIT Delhi

```
6 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Discuss with colleagues and IITians

View all Questions »
• Complete AIPMT/AIIMS Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details
Get extra Rs. 3,180 off
USE CODE: CHEM20
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details
Get extra Rs. 3,180 off
USE CODE: CHEM20