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Two circles with radii a and b touch each other externally. Another circle with radius c touches both of them externally such that they all have only one common tangent. Prove that: 1/√c = 1/√a + 1/√b CAN ANYONE SOLVE THIS PLEASE!!!>>>

Two circles with radii a and b touch each other externally. Another circle with radius c touches both of them externally such that they all have only one common tangent. Prove that:


1/√c = 1/√a + 1/√b


 


CAN ANYONE SOLVE THIS PLEASE!!!>>><<

 


 



 


Grade:10

1 Answers

SAGAR SINGH - IIT DELHI
878 Points
13 years ago

Dear student,

Its a very simple question, you just have to write condition of tangency for all the 3 circles with radii a,b and c...

Then equate and you will get the same result....

Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.

All the best.

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Askiitians Expert

Sagar Singh

B.Tech, IIT Delhi

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