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```        A uniform solid sphere of relative density 5 is released in water filled in a long vertical tube. Its terminal
velocity acheived is V. If another uniform solid sphere of same material but double the radius is released
in the same water then the terminal velocity achieved will be.```
6 years ago

510 Points
```										force (F) = 6piRkV                 (V is terminal velocity)
Fi/Ff = (Ri/Rf).(Vi/Vf)   ..........1              (i , f denotes initial & final)

F = vg(p - pw)             (v is volume)
F1/F2 = v1/v2                        (v = 4/3 piR3 )
F1/F2 = (Ri/Rf)2       ...............2
equating 1 & 2
(Ri/Rf)2 = (Vi/Vf)
Vi/Vf = 1/4
Vf = 4V
approve if u like my ans
```
6 years ago
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