0

Guest

Courses New

A liquid soap film in shape of a plane loop has an initial area 0.05 m2. If its area is slowly doubled then the increase in its surface potential energy from its initial value will be (Surface tension of liquid = 0.2 N/m).

A liquid soap film in shape of a plane loop has an initial area 0.05 m2. If its area is slowly doubled then
the increase in its surface potential energy from its initial value will be (Surface tension of liquid = 0.2
N/m).

Grade:12th Pass

2 Answers

vikas askiitian expert
509 Points
13 years ago

dE  = Tds                 

T = surface tension , ds change in area

     =(0.05)2(0.2) = 2*10-3 joules

SATYAM JAISWAL
15 Points
5 years ago
U= Ts×Area
=2×0.2×0.05= 2×10-2J
 
This is correct answer . In this question we take a change in area and we multiplied by 2 because soap drop has two layer and surface tension is given so easily you will get answer.
 
Regards, 
Satyam Jaiswal

Think You Can Provide A Better Answer ?

Other Related Questions on Discuss with colleagues and IITians

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More