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T = distance/speed = 120/v (initial time)
final time = 240/2v = 120/v (final time)
therefore time will remain same ......
We know,
s=ut+1/2 at2
but since the train is going with uniform velocity, hence the acceleration is zero.
therefore,
s=ut
In the first case,
120=vt
t=120/v
In the second case,
240=2vt
Hence, the time in both the cases, time taken will be the same.
Please Approve!!
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