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Vikas TU Grade: 12th Pass
        A takes 5 days more than B to do a certain job and 9 days more than C; A and B together can do the job in

the same time as C. Then A alone can do the job in
6 years ago

Answers : (1)

Mayank Jain
37 Points
										

Let the day taken by C alone be n


so in one day work done by C=1/n


Time taken by A to do the same work = n+9 days


so in one day work done by A=1/n+9


Also A and B can together do the work in same time as C


so work done in one day by A and B together = work done by C in one day=1/n


let work done by B in one day be b


so 1/n=b+(1/n+9)


so b=9/n(n+9)


 


Hence B takes n(n+9)/9 days to finish the work alone.


According to Question days taken by A alone = days taken by B alone +5


so n+9=n(n+9)/9+5


solving this n2=36 and n=6 days


Hence A alone can do the job in n+9=6+9=15 days time


 


Please approve if correct.

6 years ago
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