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What is the reduction potential of the following half cell under the specified conditions and at 298 K? (i) Cl2 + 2e ---> 2Cl- (negative ion), [Cl-] = 0.10M, partial pressure of Cl2 = 0.10 atm. I need to know how do we substitute the partial pressure of cl2, I was said that first we have to convert it into concentration and then substitute in nernst equation, but i dont know the exact answer. Could anyone help me out with this please?


What is the reduction potential of the following half cell under the specified conditions and at 298 K?

      (i) Cl2 + 2e ---> 2Cl- (negative ion), [Cl-] = 0.10M, partial pressure of Cl2 = 0.10 atm.

I need to know how do we substitute the partial pressure of cl2, I was said that first we have to convert it into concentration and then substitute in nernst equation, but i dont know the exact answer. Could anyone help me out with this please?



 

Grade:12

1 Answers

SAGAR SINGH - IIT DELHI
878 Points
13 years ago

Dear student,

Use pressure to calculate concentration-

c=P/RT

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Sagar Singh

B.Tech, IIT Delhi

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