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abhishek athreya Grade: 11
        

A simple pendulum with solid metal bob has a time period T  . What will be the period of the same pendulum if it is made to oscillate in a non-viscous liquid of density one-tenth of the metal of the bob?

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

T = 2pi(L/g)1/2        ...........1


finally weight of body is reduced in water = (dbVbg - dLVbg)


db,dL are dencity is bob & liquid , Vb = volume of bob


mgeff = Vbg(db-dL)


dL = db/10          (given)


so , mgeff  = Vbdbg(9/10)


       geff = 9g/10  


time period = T1 = 2pi(L/geff)1/2           ................2


divide 2 by 1


T1/T = (10/9)1/2


T1 = (10/9)1/2T


approve my ans if u like it

6 years ago
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