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two identical pith balls are charged by rubbing against each other.they are suspended from a horizontal rod through two strings of length 20cm each,the sepration between the sucpension points being 5 cm.in equlibirium,the sepration between the balls is 3 cm find the mass of each ball and tension in the strings..the charge on each ball hasa magnitude 2×10^-8 cm?
plzz can u xplain each step..plz....cz i need full step ......
As they're charged by rubbing..whatever is the charge on one ball..must be equal to be charge on the other magnitude wise..and will be of opposite charge...and..now..you know that 2 unlike charges attract and hence the 2 pith balls should attract each other..draw the situation given in the question..now THINK..what will happen..if you dont get any idea..RETHINK !..they both will attract each other..but are tied to a string and hence the strings will align themselves at an angle with the initial position..let the angle be theta..you can find..the trigonometric ratio..like..you can find sin theta..after that balance the forces..take the componants of the forces ie tension and weight force and the coloumb force..balance it..you'll get equations..solve it.
THINK !..you need to develop your problem solving skills to crack the IITJEE..which you may earn only when you think..good luck brother !
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