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Vaibhav Mathur Grade: 12
        

If (1+x)n=C0+C1x+C2x2....+Cnxn,then


C0+3C1+5C2+...+(2n+1)Cn  is equal to


(a)n*2n


(b)(n+1)2n


(c)n*2n+1


(d)0

7 years ago

Answers : (2)

askiitian expert akshay singh
8 Points
										

hi vaibhav,


  solve this problem using the same trick,put n=2


(1+x)=1+2x+x,so c0=1,c1=2,c2=1


c0+3c1+5c2=12,now solve all the options with n=2 u'll find option(b)(n+1)2n=12 is the right answer.

7 years ago
Pratham Ashish
17 Points
										

hi vaibhav,


in dis problem , u can write d general term of d series dat u hav to find,


Tr = (2r + 1)Cr


now apply summation ,


S =2 *  sum r* Cr + sum Cr


sum Cr can be calculated by putting 1 in place of x in (1+x)^n, dat will give 2^n


for r * Cr , u just differentiate (1+x)^n  and again put 1 in place of x , den u will get n*2^(n-1)=C1+2*C2+.......


d final expression after adding will be n*2^n +2^n = (n+1)2^n

7 years ago
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