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If the point P(x.y) be equidistant from the points A(a+b,b-a) and B(a-b,a+b), the prove that bx=ay.
Dear chanchal ,
i suggest simply apply hero's formula and use PA= PB or PA2 = PB2
x-(a+b)2 + y -(b-a)2 = x-(a-b)2 + y -(a+b)2
solving we get bx =ay. i don't think there is a need of doing angles equal or other method when this works perfectly.
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ans if pts r equidistant then distance between them is equal
AP2 = BP2 u can prove that
OR,
if P is equidistant from A or B
x=1(a+b) + 1(a-b)/2 = a. ----1)
y=1(a+b) + 1(b-a)/2 = b. ----2)
THEN DIVIDE 1) and 2)...
x/y=a/b =>bx=ya HENCE PROVED..
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