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`        If the point P(x.y) be equidistant from the points A(a+b,b-a) and B(a-b,a+b), the prove that bx=ay.`
7 years ago

68 Points
```										Dear chanchal ,
i suggest simply apply hero's formula and use PA= PB or PA2 = PB2
x-(a+b)2 + y -(b-a)2 = x-(a-b)2 + y -(a+b)2
solving we get bx =ay. i don't think there is a need of doing angles equal or other method when this works perfectly.
Please feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation. Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.
```
7 years ago
gOlU g3n|[0]uS
42 Points
```										ans   if pts r equidistant then distance between them is equal
AP2 =  BP2  u can prove that
OR,
if P is equidistant from A or B
x=1(a+b) + 1(a-b)/2 =  a. ----1)
y=1(a+b) + 1(b-a)/2 = b.  ----2)
THEN DIVIDE 1) and 2)...
x/y=a/b =>bx=ya  HENCE PROVED..
```
7 years ago
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