i did nt underst00d the f0II0wing Iine given in the n0tes

Let P(x₁, y₁) and Q(x₂, y₂) be two neighbouring points on the parabola y² – 4ax. Then the equation of the line joining P and Q is

y – y₁ = (y₂-y₁) / (x₂-x₁ ) (x – x₁) …… (1)

-kiran

Question

i did nt underst00d the f0II0wing Iine given in the n0tes

Let P(x₁, y₁) and Q(x₂, y₂) be two neighbouring points on the parabola y² – 4ax. Then the equation of the line joining P and Q is

y – y₁ = (y₂-y₁) / (x₂-x₁ ) (x – x₁) …… (1)

-kiran

Badiuddin askIITians.ismu Expert · Answer

Dear kiran

we know that slope of the line joining by two point is

m =y2 -y1 /x2 -x1

now we know that equation of line passes through a point and slope m is

y-y1 =m( x-x1)

now put the value of m and you will get the desired result

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i did nt underst00d the f0II0wing Iine given in the n0tes Let P(x 1 , y 1 ) and Q(x 2 , y 2 ) be two neighbouring points on the parabola y 2 – 4ax. Then the equation of the line joining P and Q is y – y 1 = (y 2 -y 1 ) / (x 2 -x 1 ) (x – x 1 ) …… (1) -kiran

i did nt underst00d the f0II0wing Iine given in the n0tes

Let P(x₁, y₁) and Q(x₂, y₂) be two neighbouring points on the parabola y² – 4ax. Then the equation of the line joining P and Q is

y – y₁ = (y₂-y₁) / (x₂-x₁ ) (x – x₁) …… (1)

-kiran

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i did nt underst00d the f0II0wing Iine given in the n0tes Let P(x 1 , y 1 ) and Q(x 2 , y 2 ) be two neighbouring points on the parabola y 2 &ndash; 4ax. Then the equation of the line joining P and Q is y &ndash; y 1 = (y 2 -y 1 ) / (x 2 -x 1 ) (x &ndash; x 1 ) &hellip;&hellip; (1) -kiran

i did nt underst00d the f0II0wing Iine given in the n0tes Let P(x1, y1) and Q(x2, y2) be two neighbouring points on the parabola y2 – 4ax. Then the equation of the line joining P and Q is y – y1 = (y2-y1) / (x2-x1 ) (x – x1) …… (1) -kiran