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vardaan kumar Grade: 11
        

A HORIZONTAL FORCE F=mg/3 IS APPLIED ON THE UPPER SURFACE OF A UNIFORM CUBE OF MASS m AND SIDE a WHICH IS RESTING ON A ROUGH HORIZONTAL SURFACE HAVING u=1/2.THE DISTANCE B/W LINES OF ACTION OF mg and normal reaction is?

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear vardaan



let distance between line of action of mg and N is x


so verticle force balance 


N=mg


clearly mg/3 is less than the maximum static friction force .


so only mg/3 static friction force will act .


now torque balance from the center of the cube


mg/3 *a/2  + mg/3 *a/2  = N*x


mga/3 =N*x


mga/3 = mgx


 x =a/3


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Badiuddin

7 years ago
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