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in an X-ray apparatus an electron is accelerated by a stop through a 10kV potential difference Calculates the maximum force that a magnetic field of 0.957T can exert on this electron.

in an X-ray apparatus an electron is accelerated by a stop through a 10kV potential difference Calculates the maximum force that a magnetic field of 0.957T can exert on this electron.

Grade:12

1 Answers

Arun
25750 Points
3 years ago
If electrons are accelerated to a velocity v by a potential difference V and then allowed to collide with a metal target, the maximum frequency of the X-rays emitted is given by the equation:
mv 
2
 =eV=hν
 
or, λ 
min
​ 
 = 
10 
3
 
1240
​ 
 ∗10 
−9
 =124nm=12.4A 
∘

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