If P (1, 2), Q(4, 6), R(5, 7) and S(a, b) are the vertices of a parallelogram PQRS, then : Options: a = 2, b = 4 a = 3, b = 4 a = 2, b = 3 a = 3, b = 5 I am getting the answer by finding mid points of diagonals but not by equating the slopes of opposite sides. Why?

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Himanshu · Answer

Equate slope of PQ=RS & then by PS=QR.b-7/a-5=6-2/4-1. By solving this equation you get 3b=4a+1.And by equating slope of PS=QR b-2/a-1=7-6/5-4 . You get b=a+1.so by solving these 2 equations you get a=2&b=3.

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If P (1, 2), Q(4, 6), R(5, 7) and S(a, b) are the vertices of a parallelogram PQRS, then : Options: a = 2, b = 4 a = 3, b = 4 a = 2, b = 3 a = 3, b = 5 I am getting the answer by finding mid points of diagonals but not by equating the slopes of opposite sides. Why?

If P (1, 2), Q(4, 6), R(5, 7) and S(a, b) are the vertices of a parallelogram PQRS, then :
Options:
a = 2, b = 4
a = 3, b = 4
a = 2, b = 3
a = 3, b = 5

I am getting the answer by finding mid points of diagonals but not by equating the slopes of opposite sides. Why?

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If P (1, 2), Q(4, 6), R(5, 7) and S(a, b) are the vertices of a parallelogram PQRS, then : Options: a = 2, b = 4 a = 3, b = 4 a = 2, b = 3 a = 3, b = 5 I am getting the answer by finding mid points of diagonals but not by equating the slopes of opposite sides. Why?

If P (1, 2), Q(4, 6), R(5, 7) and S(a, b) are the vertices of a parallelogram PQRS, then :Options:a = 2, b = 4a = 3, b = 4a = 2, b = 3a = 3, b = 5 I am getting the answer by finding mid points of diagonals but not by equating the slopes of opposite sides. Why?

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If P (1, 2), Q(4, 6), R(5, 7) and S(a, b) are the vertices of a parallelogram PQRS, then :
Options:
a = 2, b = 4
a = 3, b = 4
a = 2, b = 3
a = 3, b = 5

I am getting the answer by finding mid points of diagonals but not by equating the slopes of opposite sides. Why?