Hi, I have a sum on Permutation & Combination. Its as follows. What is the total number of ways in which Robert can distribute 9 distinct chocolates among 8 people such that each one gets atleast one chocolate?

Question

Harsh Patodia · Answer

Hi

First u need to select 8 chocolates out of nine and distribute one to each
(Since each has to get atleast 1)
This can be done in ⁹C₈x 8! ways

Now the remaing 1 chocolate can be given to any one student i.e 8choices
So total ways will be 9x⁹C₈x8! ways.

Meeta · Answer

Hi, Thanks for the reply. But the answer given is different, it says 36 * 8! is the correct answer. Please let me know how to get to that. Thanks

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Hi, I have a sum on Permutation & Combination. Its as follows. What is the total number of ways in which Robert can distribute 9 distinct chocolates among 8 people such that each one gets atleast one chocolate?

Hi,
I have a sum on Permutation & Combination. Its as follows. What is the total number of ways in which Robert can distribute 9 distinct chocolates among 8 people such that each one gets atleast one chocolate?

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Hi, I have a sum on Permutation & Combination. Its as follows. What is the total number of ways in which Robert can distribute 9 distinct chocolates among 8 people such that each one gets atleast one chocolate?

Hi,I have a sum on Permutation & Combination. Its as follows. What is the total number of ways in which Robert can distribute 9 distinct chocolates among 8 people such that each one gets atleast one chocolate?

2 Answers

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Hi,
I have a sum on Permutation & Combination. Its as follows. What is the total number of ways in which Robert can distribute 9 distinct chocolates among 8 people such that each one gets atleast one chocolate?