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Dear vivek
mg force is acting on the liquid element in downward direction
and inertial force ma is acting in the apposite direction of acceleration
let F is resultant of these two
F2 =(mg)2 + (ma)2 + 2(mg)(ma)cos60
this force F makes and angel Φ with mg
tanΦ =ma sin60 /(mg + ma cos60)
T is apposite to F
and free surface of liquid will be perpendicular to T
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