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`        the ends of a rod of length 'l' move on 2 mutually perpendicular lines. Find the locus of the point on the rod, which divides it in the ratio 2:1`
7 years ago

147 Points
```										Dear shreyans

l2 =a2+ b2
h= a/3   or a = 3h
k = b/3   or b= 3k
so  l2 =9h2+9k2
h2+k2 = (l/3)2
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation. All the best. Regards,Askiitians ExpertsBadiuddin
```
7 years ago
Abhimanyu
10 Points
```										6854-2094_7662_untitled.JPG  l2 =a2+ b2 h= a/3   or a = 3h k = 2b/3   or b= 3k/2so  l^2 =9h^2+(9k^2)/4  h^2+(k^2)/4 = (l/3)^2or, x^2+(y^2)/4=(l^2)/9Done!!!!!
```
3 months ago
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