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1) the two sequences of numbers {1,4,16,64,.............} and

{3,12,48,192,....................} are mixed as {1,3,4,12,16,48,64,192,.......}.If one number in the mixed series is 1048576 then its just preceeding number is.

(A)262144  (B)786432  (C)3245728  (D) NOT POSSIBLE TO FIND IT





7 years ago


Answers : (1)

										It can be seen that the first sequence is 4^n-1 where n=1,2,3,....

Second sequence is 3*4^n-1 where n=1,2,3,.....
1048576=4^10. So this is the 11th term of the first series.
The preceeding term will be the 10th term of the second series.

So substitute n=10 in the second series, we get 3*4^9 which will evidently be option B.
7 years ago

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