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`        find the four numbers in G.P. in which third term is greater than first by 9, second term is greater than foutht by 18 ? `
7 years ago

419 Points
```										Dear Raju
let the numbers are a, ar, ar2, ar3
from the given conditions
ar2-a=9   ........(1)
ar-ar3=18   ......(2)
dividing (2) by (1)
(r-r3)/(r2-1)=18/9
r(1-r2)/(r2-1)=2
r= -2
putting r=-2 in (1)
a=3
hence numbers will be 3,-6,12,-24

All the best.
AKASH GOYAL

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```
7 years ago
510 Points
```										let the numbers are   a/r  ,  a  ,ar  , ar2

third term is greater than first by 9 so

ar=a/r +9 or  ar2 =a+9r...........1

also second term is greater than fourth by 18 so

a =ar2 +18.......2

solving 1 and 2 we get r=-2 & a=-6

therefore numbers are  3 , -6 ,12 ,-24
```
7 years ago
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