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				   This is the question of jee 2010 , paper 2 maths...

Q)Let S = {1, 2, 3, 4}. The total number of unordered pairs of disjoint subsets of S is equal to
(A) 25 (B) 34
(C) 42 (D) 41
Sol. (D)

the solution I got at a site was

Total number of unordered pairs of disjoint subsets
(3^4 + 1)/2 = 41

Please tell how did they reach at this solution?..

6 years ago


Answers : (1)


Dear shubhi,

There is a generalised formula: 3^n+1/2 so you can use this formula....

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Askiitians Expert

Sagar Singh

B.Tech, IIT Delhi

6 years ago

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