If α,β be the roots of x 2 - a(x-1)-b=0,then the value of 1/α 2 -aα +1/β 2 -αβ +2/a+b is (ans I got is 4b/a 2 -b 2 .Its given ans is 0)

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If &alpha;,&beta; be the roots of x 2 - a(x-1)-b=0,then the value of 1/&alpha; 2 -a&alpha; +1/&beta; 2 -&alpha;&beta; +2/a+b is (ans I got is 4b/a 2 -b 2 .Its given ans is 0)

Rohit Singh · Answer

I think b should be positive in the equation then the ans will be 0.

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If α,β be the roots of x 2 - a(x-1)-b=0,then the value of 1/α 2 -aα +1/β 2 -αβ +2/a+b is (ans I got is 4b/a 2 -b 2 .Its given ans is 0)

If α,β be the roots of x²- a(x-1)-b=0,then the value of 1/α²-aα +1/β²-αβ +2/a+b is (ans I got is 4b/a²-b².Its given ans is 0)

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If α,β be the roots of x 2 - a(x-1)-b=0,then the value of 1/α 2 -aα +1/β 2 -αβ +2/a+b is (ans I got is 4b/a 2 -b 2 .Its given ans is 0)

If α,β be the roots of x2- a(x-1)-b=0,then the value of 1/α2-aα +1/β2-αβ +2/a+b is (ans I got is 4b/a2-b2.Its given ans is 0)

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If α,β be the roots of x²- a(x-1)-b=0,then the value of 1/α²-aα +1/β²-αβ +2/a+b is (ans I got is 4b/a²-b².Its given ans is 0)