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Neel Pratik Bhatt Grade: 11
        

  1. Respected Sir/Ma'am :


       I have a liitle problem with solving this problem and i am currently in Grade:9. The problem is as follows:


If x=9-4*(5)^1/2 then find the value of :


(x)^1/2-1/(x)^1/2                       ;[(n)^1/2 which is Root:n)].


Thank You in advance Sir/Ma'am.


Also i want to know if i have any doubts in the problem solving, how can i approach to you, imean how can i consult you back?

7 years ago

Answers : (2)

Askiitians Expert Soumyajit IIT-Kharagpur
28 Points
										

Dear Neel,


Ans:- √x - 1/√x=(√(√x - 1/√x))²


                       =√(x+1/x- 2)


                             Putting the values and using 9-4√5 =1/(9+4√5) we get. The ans is=4


 


Please feel free to post as many doubts on our discussion forum as you can. If you find any question
Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We
are all IITians and here to help you in your IIT JEE preparation.
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All the best Neel !!!


 



Regards,


Askiitians Experts


SOUMYAJIT IIT_KHARAGPUR

7 years ago
Vijay Luxmi Askiitiansexpert
357 Points
										

Dear Neel,


√x - 1/√x=(√(√x - 1/√x))²


                       =√(x+1/x- 2)


                             Putting the values and using 9-4√5 =1/(9+4√5) we get. The ans is=4


 


Please feel free to post as many doubts on our discussion forum as you can. If you find any question
Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We
are all IITians and here to help you in your IIT JEE preparation.
win exciting gifts by answering the questions on Discussion Forum.

7 years ago
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