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Jitender Singh IIT Delhi
askIITians Faculty 158 Points
9 years ago
Ans:Hello student, please find answer to your question
-2 < tanx < \sqrt{3}
tanx = \sqrt{3}
x = n\pi + \frac{\pi }{3}
tanx = -2
x = tan^{-1}(-2)
x =- tan^{-1}(2)
x =n\pi - tan^{-1}(2)
\Rightarrow n\pi - tan^{-1}(2)< x< n\pi + \frac{\pi }{3}

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