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```				   A and B throw with a pair of dice.A wins if he throws 6 before B throws 7 and B wins if he throws 7 before A throws 6.if A begins, what is his change of winning---------------
```

6 years ago

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```										The sum 6 can be got in 5 ways. [i.e., (1,5) , (2,4) , (3,3) , (4,2) , (5,1) ] . The probability of A throwing 6 is 5/36 . Thus , the probabilityof A not throwing 6 is 1 – 5/36 = 31/36 . similarly the probability of B throwing 7 is 6/36 and the probability of B not throwing 7 = 1 – 6/36 = 30/36 = 5/6 . Now A can win if he throws 6 in the first , third , fifth , …throws. Hence , the chance of A winning = 0.1
```
one year ago

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