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why do we use exp(-iwt) as a kernel function in fourier transform?

why do we use exp(-iwt) as a kernel function in fourier transform?
 

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1 Answers

Vijay Mukati
askIITians Faculty 2590 Points
8 years ago
Hi, Fourier transform is a special case of the Laplace transform in which real part is zero. Therefore the only term left is imaginary and is equal to -jwt. F-transform is only defired for the stable signals/systems only.

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