0

Guest

Courses New

what is the differential equation of thetangents of the parabola y=x^2?

what is the differential equation of thetangents of the  parabola y=x^2?

Grade:Select Grade

1 Answers

Vikas TU
14149 Points
7 years ago
differential equation of thetangents of the  parabola y=x^2
is given by : 
y = mx – am^2
a =1/4
y = mx -m^2/4................................(1)
Since the tangent eqn. has only one constant
differentiate ir w.r.t x one time and then substitute,
dy/dx = m ------------------------(2)
in eqn. (1)
we get,
y = xdy/dx – (dy/dx)^2/4 is required differential eqn.

Think You Can Provide A Better Answer ?

Other Related Questions on Differential Calculus

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More