please can you tell me How intigration of tanx dx=log|secx|+c

Question

Neelam Papanai · Answer

Here tanx=sinx/cosxNow let cosx=tSo -sinx dx=dtSoInte of tanx = -dt/t = -log tNow log a to power b=b log aSo -log t= log of 1/tThat is log of 1/cos xThat is sec x

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please can you tell me How intigration of tanx dx=log|secx|+c

please can you tell me
How intigration of tanx dx=log|secx|+c

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please can you tell me How intigration of tanx dx=log|secx|+c

please can you tell meHow intigration of tanx dx=log|secx|+c

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please can you tell me
How intigration of tanx dx=log|secx|+c