let (tana)x+(sina)y=a and (acoseca)x+(cosa)y=1 be two straight lines , a being the parameter .Let P be the point of intersection of two lines. In limiting position when a--0 , the co-ordinates of P are

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let (tana)x+(sina)y=a and (acoseca)x+(cosa)y=1 be two straight lines , a being the parameter .Let P be the point of intersection of two lines. In limiting position when a-->0 , the co-ordinates of P are

Sayantan Mondal · Answer

firstly this is a good question... and is a bit tricky... here comes 2 steps-- firstly solve the two lines for finding the point of intersection. i.e, x=[acosa-sina]/[sina-a]and y=[sin^2 a-a^2 cosa]/[sin^2 acosa-asinacosa]. then comes the important part, apply lim a tends to 0...[for my preference i used l Hospital’s Rule and the answer is (-1,_).. icouldnot do that sorry... BUT I AM SURE THE PROCESS IS O.K

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let (tana)x+(sina)y=a and (acoseca)x+(cosa)y=1 be two straight lines , a being the parameter .Let P be the point of intersection of two lines. In limiting position when a-->0 , the co-ordinates of P are

let (tana)x+(sina)y=a and (acoseca)x+(cosa)y=1 be two straight lines , a being the parameter .Let P be the point of intersection of two lines. In limiting position when a-->0 , the co-ordinates of P are

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let (tana)x+(sina)y=a and (acoseca)x+(cosa)y=1 be two straight lines , a being the parameter .Let P be the point of intersection of two lines. In limiting position when a-->0 , the co-ordinates of P are

let (tana)x+(sina)y=a and (acoseca)x+(cosa)y=1 be two straight lines , a being the parameter .Let P be the point of intersection of two lines. In limiting position when a-->0 , the co-ordinates of P are

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