In an isosceles triangle ABC in which AB=AC and AD is median through A to the side BC such that BC=8cm and AD=6cm then the distance between the mid point of BD and AC is

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I don`t able to understand that what is distance between the mid point of BD and AC is as BD=4,CD=4, AD=6 then please elaborate the question.

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In an isosceles triangle ABC in which AB=AC and AD is median through A to the side BC such that BC=8cm and AD=6cm then the distance between the mid point of BD and AC is

In an isosceles triangle ABC in which AB=AC and AD is median through A to the side BC such that BC=8cm and AD=6cm then the distance between the mid point of BD and AC is

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In an isosceles triangle ABC in which AB=AC and AD is median through A to the side BC such that BC=8cm and AD=6cm then the distance between the mid point of BD and AC is

In an isosceles triangle ABC in which AB=AC and AD is median through A to the side BC such that BC=8cm and AD=6cm then the distance between the mid point of BD and AC is

1 Answers

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Other Related Questions on Differential Calculus

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