e x =√1+t-√1-t/√1+t-√1-t and tany/2 then dy/dx at t=1/2 is?

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e x =&radic;1+t-&radic;1-t/&radic;1+t-&radic;1-t and tany/2 then dy/dx at t=1/2 is?

Pankaj · Answer

I am not able to interpret your query. Please write down the problem clearly so that I can provide you the meaningful answer. Thanks & Regards Pankaj Singh askIITians Faculty

Sumit Majumdar · Answer

Dear student, From the question it appears exponent would be equal to 1 and not sure how y is related to t or x. Please check the question and ask again. Regards Sumit

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e x =√1+t-√1-t/√1+t-√1-t and tany/2 then dy/dx at t=1/2 is?

e^x=√1+t-√1-t/√1+t-√1-t and tany/2 then dy/dx at t=1/2 is?

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e x =√1+t-√1-t/√1+t-√1-t and tany/2 then dy/dx at t=1/2 is?

ex=√1+t-√1-t/√1+t-√1-t and tany/2 then dy/dx at t=1/2 is?

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e^x=√1+t-√1-t/√1+t-√1-t and tany/2 then dy/dx at t=1/2 is?