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				   show that  y^2 = ax^2 + bx +c then y^3(d^2y/dx^2) is constant


6 years ago

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										Ans:$y = \sqrt{ax^{2}+bx+c}$$\frac{dy}{dx} = \frac{2ax+b}{2\sqrt{ax^{2}+bx+c}}$$\frac{d^{2}y}{dx^{2}} = \frac{4ac-b^{2}}{4(ax^{2}+bx+c)^{3/2}}$$y^{3}.\frac{d^{2}y}{dx^{2}} = (ax^{2}+bx+c)^{3/2}.\frac{4ac-b^{2}}{4(ax^{2}+bx+c)^{3/2}} = \frac{4ac-b^{2}}{4}$Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty

2 years ago

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