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				   if the function f(x)=2x^2-kx+5 is increased on [1,2],then k lies in interval ________


6 years ago

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										Ans:If f(x) is increasing in [1,2], then f’(x) > 0 in the interval$f(x)= 2x^{2}-kx+5$$f^{'}(x)= 4x-k > 0$$4-k > 0$$8-k > 0$$\Rightarrow k< 4$$\Delta \geq 0$$k^{2}-4.2.5\geq 0$$(k-\sqrt{40})(k+\sqrt{40})\geq 0$$\Rightarrow k\geq \sqrt{40}, k\leq -\sqrt{40}$$\Rightarrow k\leq -\sqrt{40}$Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty

2 years ago

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