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f(x)= 1+2sinx + 3(cosx)^2, 0<=x<=2Π/3 is
a) min at x= Π/2
b) min at x= Π/6
Dear Shefali Sharma,
Ans:- f(x)=1+2sinx +3cos²x
Differentiating WRT x we get = 2cosx-6sinx cosx and
the 2nd order differential is= -2sinx-6cos2x
putting dy/dx=0 we get sinx=1/3 && cosx=0
Hence applying the conditions for max and minima we get the values as
Max value:-13/3
Min value:-3
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All the best Shefali Sharma !!!
Regards,
Askiitians ExpertsSoumyajit Das IIT Kharagpur
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