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				   using L hospital rule lim x=0 x-sinxcosx/x3


6 years ago

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										Ans:$L = lim(x\rightarrow 0)\frac{x-sinx.cosx}{x^{3}}$$L = lim(x\rightarrow 0)\frac{x-\frac{sin2x}{2}}{x^{3}}$$L = lim(x\rightarrow 0)\frac{1-cos2x}{3x^{2}}$$L = lim(x\rightarrow 0)\frac{2sin2x}{6x}$$L = \frac{2}{3}lim(x\rightarrow 0)\frac{sin2x}{2x} = \frac{2}{3}$Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty

2 years ago

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