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`        Q.) Find f(x) if f(x)=x+∫xy2+x2yƒ(y)dy. limits of integration - frm 0 to 1.`
7 years ago

147 Points
```										Dear navroze
f(x)=x+o∫1[xy2+x2yƒ(y)]dy
f(x) = x+ x/3  + x2o∫1yƒ(y)dy
o∫1yƒ(y)]dy    it is a constant quantity let it is equal to c
so
f(x)  = 4 x/3  + cx2
or f(y) =  4 y/3  + cy2
now  c =o∫1yƒ(y)dy
put value of f(y)
c= o∫1y[4  y/3  + cy2]dy
c = 4/9 + c/4
3c/4 = 4/9
c =16/27

so f(x) = 4  x/3  + 16/27 x2
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best. Regards,Askiitians ExpertsBadiuddin
```
7 years ago
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