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ANAM V. RANGA REDDY Grade: Upto college level
`        A man is running along a circular track has a speed of 10 kmph. A source of light is at the center of the circular track. A wall along the tangent from which he starts. what is the speed of the shadow of the man on the wall when he covers 1/8 th of the track.`
7 years ago

147 Points
```										Dear ANAM

from the figur when man is at point P shadow will be at point B
tanΘ =x/r
x =r tanΘ
differentiate
dx/dt = r sec2Θ dΘ/dt
=r sec2Θ * W      where w is angular velocity
=v sec2Θ
at 1/8 th of the track it will cover an angel  π/4
so dx/dt = 10* 2 =20 kmph
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```
7 years ago
Rahul
11 Points
```										This means when particle move from point A along P..the shadow move along AB...if we assume AP=10..then shadow must travel AB in 1 hr ....then 2*pi*r=80...subtituting r in tan formula we dont get x=20...can u tel me wt wrong i did in this?
```
one year ago
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