Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```

show that the equation x4+4x3-4x-13=0 has two real roots and two imaginary roots.

```
7 years ago

Jitender Singh
IIT Delhi
158 Points
```										Ans:$f(x) = x^{4} +4x^{3}-4x-13 = 0$$f(1) = 1^{4} +4.1^{3}-4.1-13 = -12$$f(2) = 2^{4} +4.2^{3}-4.2-13 = 27$→There is one root lie b/w (1, 2)$f(-3) = (-3)^{4} +4.(-3)^{3}-4.(-3)-13 = -28$$f(-4) = (-4)^{4} +4.(-4)^{3}-4.(-4)-13 = 3$→There is another root lie b/w (3, 4) which is close to 4.-> There is no other inteval like this in which f(x) changes its sign.-> So the other two roots are imaginary.Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Differential Calculus

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details