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```        Find the equation of the tangent to the curve
y = (x - 7)/{(x-2)(x-3)} at the point where it cuts the x - axis.```
7 years ago

147 Points
```										Dear
y= (x - 7)/{(x-2)(x-3)}
for sut point on x axis put y=0
x=7
so point is (7,0)
now
dy/dx =  [(x-2)(x-3)  - (x-7)(2x-5)]/{(x-2)(x-3)}2
= 1/20    at (7,0)
so euation of tangent
y-0 = 1/20 (x-7)
x-20y -7=0
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```
7 years ago
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