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        The value of 'a' for which the function
ƒ(x)={ -x3 + sin-1 a ,when 0
7 years ago

Jitender Singh
IIT Delhi
158 Points
										Ans:$f(x) = {-x^{3}+sin^{-1}a, 0< x<1}$     $= {x, x\geq 1}$The value of f(x) at x = 1 is1.For the function to have minimum at 1, left hand neighbourhood of x = 1 should be greater than f(1).$-(1)^{3}+sin^{-1}a> f(1)> 1$$sin^{-1}a> 2$which is not possible because$-1\leq sin^{-1}a\leq 1$So there is no value of ‘a’ for which f(x) has minimum at 1.Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty

3 years ago
Jitender Singh
13 Points
										Ans:There is a small mistake in the above answer.-pi/2 =-1a = Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty

3 years ago
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