Home About Us Discussion Board Articles AIEEE Packages FAQs Careers Contact Us Sign In  
  Forum  >> Differential-Calculus  >> Wavy curve method  

neeraj pawar 

Total Posted Questions : 26
   

Please explain in brief the wavy curve method & also solve this ques..

f(x)=(x-2)²(1-x)(x-3)³(x-4)²/(x+1) ≤ 0 find the value of X.




 
Win Exciting Gifts
  Post Your Reply


Total Replies: 1
Profile Message

Badiuddin askIITians.ismu Expert
[Rookie Askiitian]
My Points:  128

Total Posted Answers: 2550
 

Dear neeraj

f(x)=(x-2)²(1-x)(x-3)³(x-4)²/(x+1) ≤ 0

 (x-2)2 (x-3)2(x-4)2   is always positive

at x=2,3,4   (x-2)2 (x-3)2(x-4)2 is  zero 

so x=2,3,4 is a solution  

 

now for  (1-x)(x-3)/(x+1) ≤ 0

  or        (x-1)(x-3)/(x+1) ≥ 0


 


 

 

 

 

7357-2077_7662_untitled.JPG

so silution is [-1,1] and [3,∞) 

 

so final solution   [-1,1] and [3,∞)  and 2

Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you
the answer and detailed  solution very  quickly.

 We are all IITians and here to help you in your IIT JEE preparation.

All the best.
 
Regards,
Askiitians Experts
Badiuddin

2/8/2010 2:48:01 PM
Do you like the answer?   Yes | No

Approved / Disapproved policy, check and win exciting gifts