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Chandan Das Grade: Upto college level
```        Let f(x)=(1+b2)x2+2bx+1 n let m(b) be the minimum value of f(x).As b varies,the range of m(b) is
a.[0,1]
b.[0,1/2]
c.[1/2,1]
d.(0,1].```
7 years ago

Ramesh V
70 Points
```										f'(x) = (1+b2).2.x + 2b = 0
f'(x) = 0 implies x = -b/(1+b2)
f''(x) = (1+b2).2 > 0 means f(x) has min. at above given x
on solving for min value for f(x) at x we have
m(b) = 1/(1+b2)
its range is [0,1]
--
regards
Ramesh
```
7 years ago
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