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Chandan Das Grade: Upto college level
        

1.Find the range of 3sinx+4cosx-5.


2.If [2sinx]+[cosx]=-3,then the range of the fnctn f(x)=sinx+√3cosx in [0,2Π]is;(whr [.] denotes GIF).

7 years ago

Answers : (1)

Ramesh V
70 Points
										

(1)


3sin(x) - 4cos(x) = 5 sin(x + arcsin(-4/5))


Thus, the range of the function asin x - bcos x is
± √[(a)^2 + (b)^2]


so here its : ±5 -5


whihc is [-10,0]


(2 ) given [2sinx]+[cosx]=-3


so both sin x and cos x lies on (-0.5 , -1]


it can be written as : 2 sin (x+pi/3)


in (o,2pi ) sin (x+pi/3) range is [0.866,-1]


so its range is [1.732, -2]


--


regards


Ramesh

7 years ago
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