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pritam samanta Grade: 12
`        how to find n-th  derivative of a function f(x)=[x^(n-1)]logx what will be n-th  derivate of f(x)`
7 years ago

## Answers : (3)

147 Points
```										Dear pritam
Fn-1(x)=x(n-1)logx
differentiate
F1n-1  = xn-2 + (n-1)xn-2logx
=  xn-2 + (n-1)Fn-2
again differentiate
F2n-1 = (n-2)xn-3  + (n-1) xn-3 +(n-1)(n-2)Fn-3
similerly
Fnn-1 = (n-1)(n-2)(n-3) ........3.2.1 xn-n
=(n-1)!
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very  quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation. All the best. Regards,Askiitians ExpertsBadiuddin

```
7 years ago
Amrita
8 Points
```										this answer is wrong. The correct answer is (n-1)!/xYou can get the answer by successively differentiating and finally reaching a step where(n-1)(n-2)....(n-(n-1))D^(n-(n-1){(x^(n-n)*logx} = (n-1)! d/dx(logx) = (n-1)!/x
```
3 years ago
yeshwanth
19 Points
```										D^n (x^n logx)
```
2 years ago
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